Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.6 Rational Exponents - R.6 Exercises - Page 64: 76

Answer

$\frac{10}{a^{1/8}b^{3/2}}$

Work Step by Step

$(\frac{25^4a^3}{b^2})^{1/8}(\frac{4^2b^{-5}}{a^2})^{1/4}=(\frac{5^8a^3}{b^2})^{1/8}(\frac{2^4}{a^2b^{5}})^{1/4}=5\cdot2\cdot\frac{a^{3/8}}{b^{1/4}a^{1/2}b^{5/4}}=\frac{10}{a^{1/8}b^{3/2}}$
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