Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.6 Rational Exponents - R.6 Exercises: 49

Answer

$\color{blue}{2}$

Work Step by Step

RECALL: (1) $a^{1/n} = \sqrt[n]{a}$ (2) If $a \gt 0$, then $\sqrt[n]{a^n} = a$ Use rule (1) above to obtain: $16^{1/4} = \sqrt[4]{16}$ Since $16=2^4$, then the expression above is equivalent to: $=\sqrt[4]{2^4}$ Use rule (2) above to simplify and have: $\sqrt[4]{2^4}=\color{blue}{2}$
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