Answer
$-\dfrac{1}{64}$
Work Step by Step
RECALL:
(1) $a^{-m} = \dfrac{1}{a^m}$
(2) $\dfrac{a^m}{a^n} = a^{m-n}$
(3) $a^1=a$
Use rule (1) above to obtain:
$(-4)^{-3} = \dfrac{1}{(-4)^3}=\dfrac{1}{-64} = -\dfrac{1}{64}$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter R - Review of Basic Concepts - R.6 Rational Exponents - R.6 Exercises - Page 63: 11
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