Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.6 Rational Exponents - R.6 Exercises: 7

Answer

(a) B (b) D (c) B (d) D

Work Step by Step

RECALL: (1) $a^{-m} = \dfrac{1}{a^m}$ (2) $\dfrac{a^m}{a^n} = a^{m-n}$ (3) $a^1=a$ Thus: (a) Using rule (1) above gives: $4^{-2}=\dfrac{1}{4^2} = \dfrac{1}{16}$ Thus, the answer is $B$. (b) Using rule (1) above gives: $-4^{-2} = -\dfrac{1}{4^2} = -\dfrac{1}{16}$ Thus, the answer is $D$. (c) Using rule (1) above gives: $(-4)^{-2} = \dfrac{1}{(-4)^2} = \dfrac{1}{16}$ Thus, the answer is $B$. (d) Using rule (1) above gives: $-(-4)^{-2} = -\dfrac{1}{(-4)^2}=-\dfrac{1}{16}$ Thus, the answer is $D$.
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