Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.5 Rational Expressions - R.5 Exercises - Page 54: 70

Answer

$\frac{p^2+8p}{(2p+1)(p-5)(3p-2)}$

Work Step by Step

Step 1. Factor each denominator, we have $2p^2-9p-5=(2p+1)(p-5)$ and $6p^2-p-2=(2p+1)(3p-2)$ Step 2. The least common denominator can be identified as $(2p+1)(p-5)(3p-2)$ Step 3. Convert each expression to have the least common denominator then perform operations: $\frac{p(3p-2)}{(2p+1)(p-5)(3p-2)}-\frac{2p(p-5)}{(2p+1)(p-5)(3p-2)}=\frac{p^2+8p}{(2p+1)(p-5)(3p-2)}$
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