Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.5 Rational Expressions - R.5 Exercises: 56

Answer

$\color{blue}{\dfrac{3z+x}{z^2}}$

Work Step by Step

The expressions are not similar since they have different denominators. Make the expressions similar using their LCD which is $z^2$ to obtain: $=\dfrac{3\color{red}{(z)}}{z\color{red}{(z)}}+\dfrac{x}{z^2} \\=\dfrac{3z}{z^2}+\dfrac{x}{z^2} \\=\color{blue}{\dfrac{3z+x}{z^2}}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.