Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.4 Factoring Polynomials - R.4 Exercises: 120

Answer

$\color{blue}{(\frac{11}{5}y^2+7x)(\frac{11}{5}y^2-7x)}$

Work Step by Step

With $\frac{121}{25}y^4=(\frac{11}{5}y^2)^2$ and $49x^2=(7x)^2$, the given binomial is equivalent to: $=(\frac{11}{5}y^2)^2-(7x)^2$ Factor using the formula $a^2-b^2=(a+b)(a-b)$ with $a=\frac{11}{5}y^2$ and $b=7x$ to obtain: $=\color{blue}{(\frac{11}{5}y^2+7x)(\frac{11}{5}y^2-7x)}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.