Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.4 Factoring Polynomials - R.4 Exercises: 30

Answer

$\color{blue}{(5a-3)(2b+7)}$

Work Step by Step

Regroup: $=(10ab-6b)+(35a-21)$ Factor out $2b$ in the first and $7$ in the second group to obtain: $=2b(5a-3)+7(5a-3)$ Factor out $5a-3$ to obtain: $=\color{blue}{(5a-3)(2b+7)}$
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