Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.4 Factoring Polynomials - R.4 Exercises: 26

Answer

$(a+3)(5a^2+31a+46)$

Work Step by Step

The factor $(a+3)$ is common to both terms. Factor out $a+3$ to obtain: $=(a+3)[5(a+3)^2-2+(a+3)] \\=(a+3)[5(a+3)^2-2+a+3] \\=(a+3)[5(a+3)^2+a+1]$ Square the binomial to obtain: $\\=(a+3)[5(a^2+6a+9)^2+a+1]$ Distribute $5$ to obtain: $\\=(a+3)(5a^2+30a+45+a+1) \\=(a+3)(5a^2+31a+46)$
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