Answer
$2(z+4)(z-2)$
Work Step by Step
$(z+4)$ is in both terms, we can factor it out:
$(z+4)((3z+2)-(z+6))=(z+4)(2z-4)$
We can factor out a constant of 2 from the second term:
$(z+4)(2z-4)=(z+4)\times2\times (z-2)=2(z+4)(z-2)$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter R - Review of Basic Concepts - R.4 Factoring Polynomials - R.4 Exercises - Page 43: 24
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