Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.4 Factoring Polynomials - R.4 Exercises: 13

Answer

$8k(k^2+3)$

Work Step by Step

Note that: $8k^3=4(2)(k)(k)(k)=2(2)(2)(k)(k)(k) \\24k=3(8)(k)=3(4)(2)(k) = 3(2)(2)(2)(k)$ Thus, the greatest common factor is $2(2)(2)(k)=8k$. Factor out the $8k$ to obtain: $8k^3+24k=8k(k^2+3)$
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