Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.2 Real Numbers and Their Properties - R.2 Exercises - Page 19: 14

Answer

$\left\{-6, -\frac{12}{4}, -\frac{5}{8}, 0, \frac{1}{4}, 1, 3\right\}$

Work Step by Step

RECALL: Rational numbers are numbers that can be expressed as $\dfrac{a}{b}$ where a and b are integers and $b\ne 0$. Writing the elements of A that can be expressed as $\dfrac{a}{b}$ gives: $-6=\frac{-12}{2}$ $-\frac{12}{4}=\frac{12}{4}$ $-\frac{5}{8} = -\frac{5}{8}$ $0 = \frac{0}{1}$ $\frac{1}{4} = \frac{1}{4}$ $1 = \frac{2}{2}$ $3 = \frac{6}{2}$ All of the numbers above are rational numbers. Thus, the elements of $A$ that are elements of the set of rational numbers are: $\left\{-6, -\frac{12}{4}, -\frac{5}{8}, 0, \frac{1}{4}, 1, 3\right\}$
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