Answer
$ \frac{1}{p^2(m+n)}$
Work Step by Step
$\frac{[p^2(m+n)^3]^{-2}}{p^{-2}(m+n)^{-5}}=p^{-4}(m+n)^{-6}\times p^2(m+n)^5=p^{-2}(m+n)^{-1}=\frac{1}{p^2(m+n)}$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter R - Review of Basic Concepts - Chapter R Test Prep - Review Exercises - Page 84: 96
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