Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - Chapter R Test Prep - Review Exercises - Page 84: 90

Answer

$-\frac{16p^7}{q}$

Work Step by Step

$(8p^2q^3)(-2p^5q^{-4})=-16p^{2+5}q^{3-4}=-16p^7q^{-1}=-\frac{16p^7}{q}$
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