Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - Chapter R Test Prep - Review Exercises - Page 84: 116

Answer

$ \frac{k(\sqrt k+3)}{k-9}$

Work Step by Step

$\frac{k}{\sqrt k-3}=\frac{k}{\sqrt k-3}\times\frac{\sqrt k+3}{\sqrt k+3}=\frac{k(\sqrt k+3)}{k-9}$
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