Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - Chapter R Test Prep - Review Exercises: 79

Answer

$\dfrac {x+1}{x+4}$

Work Step by Step

$\dfrac {x^{2}+x-2}{x^{2}+5x+6}:\dfrac {x^{2}+3x-4}{x^{2}+4x+3}=\dfrac {\left( x+2\right) \left( x-1\right) }{\left( x+2\right) \left( x+3\right) }:\dfrac {\left( x+4\right) \left( x-1\right) }{\left( x+3\right) \left( x+1\right) }=\dfrac {\left( x+2\right) \left( x-1\right) }{\left( x+2\right) \left( x+3\right) }\times \dfrac {\left( x+3\right) \left( x+1\right) }{\left( x+4\right) \left( x-1\right) }=\dfrac {x+1}{x+4}$
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