Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - Chapter R Test Prep - Review Exercises - Page 83: 69

Answer

$(7m^4+3n)(7m^4-3n)$

Work Step by Step

Step 1. Rewrite the expression as $49m^8-9n^2=(7m^4)^2-(3n)^2$ Step 2. Use the formula $A^2-B^2=(A+B)(A-B)$, we have $49m^8-9n^2=(7m^4)^2-(3n)^2=(7m^4+3n)(7m^4-3n)$
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