Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - Chapter R Test Prep - Review Exercises - Page 83: 62

Answer

$5m-7+\frac{10m}{m^2-2} $

Work Step by Step

Step 1. Rewrite and factor the numerator as $5m^3-7m^2+14=5m^3-10m+10m-7m^2+14=5m(m^2-2)-7(m^2-2)+10m=(m^2-2)(5m-7)+10m$ Step 2. We have $\frac{5m^3-7m^2+14}{m^2-2}=\frac{(m^2-2)(5m-7)+10m}{m^2-2}=5m-7+\frac{10m}{m^2-2} $
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