Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - Chapter R Test Prep - Review Exercises - Page 83: 58

Answer

$\color{blue}{16a^2-24ab+9b^2}$

Work Step by Step

RECALL: $(x-y)^2=x^2-2xy+y^2$ Use the formula above with $x=4a$ and $y=3b$ to obtain: $=(4a)^2-2(4a)(3b) + (3b)^2 \\=\color{blue}{16a^2-24ab+9b^2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.