## Precalculus (6th Edition)

$\color{blue}{16y^3+42y^2-73y+21}$
Distribute each term of the binomial factor to trinomial factor to obtain: $=8y(2y^2+7y-3) -7(2y^2+7y-3)$ Distribute $8y$ and $-7$ to obtain: $=8y(2y^2)+8y(7y)-8y(3)-7(2y^2)-7(7y) - 7(-3) \\=16y^3+56y^2-24y-14y^2-49y+21$ Combine like terms to obtain: $=16y^3+(56y^2-14y^2)+(-24y-49y)+21 \\=16y^3+(56-14)y^2+(-24-49)y+21 \\=16y^3+42y^2+(-73)y+21 \\=\color{blue}{16y^3+42y^2-73y+21}$