Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 9 - Systems and Matrices - 9.1 Systems of Linear Equations - 9.1 Exercises - Page 857: 32

Answer

Inconsistent and has no solutions.

Work Step by Step

We can write the given system of equations after multiplying Equation-1 by $-2$ as: $-6x+4y=-10 \\6x-4y=8 $ Need to add above equations to eliminate $x$. $6x-4y-6x+4y=8-10 \\ 0=-2 $ Since 0 never equals -2 $(0 \ne -2)$. So, the system of equations is inconsistent and has no solutions.
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