Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 9 - Systems and Matrices - 9.1 Systems of Linear Equations - 9.1 Exercises - Page 857: 28

Answer

$$\left\{ {\left( { - 2,2} \right)} \right\}$$

Work Step by Step

$$\eqalign{ & \frac{{3x}}{2} + \,\,\frac{y}{2}\, = - 2\,\,\, \cr & \,\,\frac{x}{2} + \,\,\frac{y}{2}\, = 0\,\,\,\,\,\, \cr & {\text{Clear the denominators}} \cr & 2\left( {\frac{{3x}}{2}} \right) + \,\,2\left( {\frac{y}{2}} \right)\, = 2\left( { - 2} \right)\,\,\, \cr & \,\,2\left( {\frac{x}{2}} \right) + \,\,2\left( {\frac{y}{2}} \right)\, = 0\,\,\,\,\,\, \cr & \cr & 3x + \,\,\,y = - 4\,\,\,\left( {\bf{1}} \right) \cr & \,\,x + \,\,\,y = 0\,\,\,\,\,\,\,\left( {\bf{2}} \right) \cr & {\text{Multiply the equation }}\left( {\bf{1}} \right){\text{ by }} - 1{\text{ }} \cr & - 3x - y = 4\,\,\,\, \cr & \,\,\,\,x + \,\,\,y = 0\,\, \cr & {\text{Add both equations}} \cr & - 3x - y = 4\,\,\,\, \cr & \,\,\,\,x + \,\,\,y = 0\,\, \cr & - - - - - - - - - - - \cr & - 2x\,\,\,\,\,\,\,\,\, = 4 \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,x = - 2 \cr & {\text{Substitute }}x = - 2{\text{ into the equation }}\left( {\bf{2}} \right) \cr & - 2 + \,\,\,y = 0 \cr & y = 2 \cr & \cr & {\text{The solution set is}} \cr & \left\{ {\left( { - 2,2} \right)} \right\} \cr} $$
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