Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 7 - Trigonometric Identities and Equations - Test - Page 740: 9

Answer

$\sec^2 B=\frac{1}{1-\sin^2 B}$

Work Step by Step

Start with the right side: $\frac{1}{1-\sin^2 B}$ $=\frac{1}{\cos^2 B}$ $=(\frac{1}{\cos B})^2$ $=\sec^2 B$ Since this equals the left side, the identity has been proven.
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