Answer
$sec\left( \pi -x\right) =-secx$
Work Step by Step
$sec\left( \pi -x\right) =\dfrac {1}{\cos \left( \pi -x\right) }=\dfrac {1}{\cos \pi \cos x+\sin \pi \sin x}=-\dfrac {1}{\cos x}=-secx$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 7 - Trigonometric Identities and Equations - Summary Exercises Verifying Trigonometric Identities - Exercises - Page 696: 4
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