Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 7 - Trigonometric Identities and Equations - Summary Exercises Verifying Trigonometric Identities - Exercises: 23

Answer

$$\dfrac {\tan \left( x+y\right) -\tan y}{1+\tan \left( x+y\right) \tan y}=\tan \left( x+y-y\right) =\tan x$$

Work Step by Step

$\tan \left( \alpha -\beta \right) =\dfrac {\tan \alpha -\tan \beta }{1+\tan \alpha \tan \beta }\Rightarrow $ $$\dfrac {\tan \left( x+y\right) -\tan y}{1+\tan \left( x+y\right) \tan y}=\tan \left( x+y-y\right) =\tan x$$
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