Answer
$\dfrac {1+\cos ^{2}x}{\sin ^{2}x}$
Work Step by Step
$\cot ^{2}x+csc^{2}x=\dfrac {\cos ^{2}x}{\sin ^{2}x}+\dfrac {1}{\sin ^{2}x}=\dfrac {1+\cos ^{2}x}{\sin ^{2}x}$
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