Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 7 - Trigonometric Identities and Equations - Chapter 7 Test Prep - Review Exercises - Page 736: 10

Answer

$\cot\theta\cos\theta$

Work Step by Step

$\displaystyle \csc\theta-\sin\theta=\frac{1}{\sin\theta}-\sin\theta$ $=\displaystyle \frac{1-\sin^{2}\theta}{\sin\theta}$ $=\displaystyle \frac{\cos^{2}\theta}{\sin\theta}$ $=\displaystyle \frac{\cos\theta}{\sin\theta}\times\cos\theta$ $=\cot\theta\cos\theta$
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