Answer
$2\rightarrow E$
Work Step by Step
$\dfrac {2\tan \alpha }{1-\tan ^{2}\alpha }=\tan 2\alpha \Rightarrow \dfrac {2\tan 15}{1-\tan ^{2}15}=\tan \left( 2\times 15\right) =\tan 30=\dfrac {\sqrt {3}}{3}\Rightarrow $
$2\rightarrow E$
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