Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 7 - Trigonometric Identities and Equations - 7.3 Sum and Difference Identities - 7.3 Exercises - Page 679: 59

Answer

$1$

Work Step by Step

$\sin \dfrac {\pi }{5}\cos \dfrac {3\pi }{10}+\cos \dfrac {\pi }{5}\sin \dfrac {3\pi }{10}=\sin \left( \dfrac {\pi }{5}+\dfrac {3\pi }{10}\right) =\sin \dfrac {\pi }{2}=1$
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