Answer
$15^0$
Work Step by Step
$\tan \alpha =\cot \theta \Rightarrow \alpha +\theta =\dfrac {\pi }{2}$
$\tan \theta =\cot \left( 45+2\theta \right) \Rightarrow \theta +45^0+2\theta =\dfrac {\pi }{2}=90^0\Rightarrow \theta =15^0$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 7 - Trigonometric Identities and Equations - 7.3 Sum and Difference Identities - 7.3 Exercises - Page 679: 35
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