Answer
$\cos \left( -52^{0}14'\right) =\cos \left( 52^{0}14'\right) $
Work Step by Step
$\sin 142^{0}14'=\cos \left( 90^{0}-142^{0}14'\right) =\cos \left( -52^{0}14'\right) =\cos \left( 52^{0}14'\right) $
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