Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 7 - Trigonometric Identities and Equations - 7.3 Sum and Difference Identities - 7.3 Exercises: 23

Answer

$\sin \dfrac {5\pi }{12}$

Work Step by Step

$\cos \dfrac {\pi }{12}=\sin \left( \dfrac {\pi }{2}-\dfrac {\pi }{12}\right) =\sin \dfrac {5\pi }{12}$
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