Answer
(a) $\frac{\pi}{2}\ rad$
(b) $10\pi\ cm$
(c) $\frac{5\pi}{3}\ cm/sec$
Work Step by Step
Given $r=20\ cm, \omega=\frac{\pi}{12}\ rad/sec, t=6\ sec$, we have:
(a) the angle generated by P in time t is $\theta=\omega t=\frac{\pi}{12}\times6=\frac{\pi}{2}\ rad$
(b) the distance traveled by P along the circle in time t is $s=r\theta=10\pi\ cm$
(c) the linear speed of P is $v=\omega r=\frac{\pi}{12}\times20=\frac{5\pi}{3}\ cm/sec$
