Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 6 - The Circular Functions and Their Graphs - 6.1 Radian Measures - 6.1 Exercises - Page 576: 95

Answer

$0.20\ km$

Work Step by Step

Given radius of the track $r=3.5\ km$ and the subtend angle $\theta=3^\circ20'=(\frac{10}{3})^\circ$, the length of the train, which equals to the arc length, can be found as $L=r\theta=3.5\times(\frac{10}{3})^\circ\times\frac{\pi}{180^\circ}\approx0.20\ km$
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