Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - 5.3 Trigonometric Functions Values and Angle Measures - 5.3 Exercises - Page 532: 52

Answer

$a=12;$ $b=12\sqrt {3}$ $c=12\sqrt {6};$ $d=c=12\sqrt {6}$

Work Step by Step

$a=24\times \cos 60^{0}=24\times \dfrac {1}{2}=12;$ $b=24\times \sin 60^{0}=12\sqrt {3}$ $c=\dfrac {b}{\cos 45}=\dfrac {12\sqrt {3}}{\dfrac {\sqrt {2}}{2}}=12\sqrt {6};$ $d=c=12\sqrt {6}$
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