Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - 5.3 Trigonometric Functions Values and Angle Measures - 5.3 Exercises: 42

Answer

$\dfrac {\sqrt {2}}{2}$

Work Step by Step

$\sin 45^{0}=\dfrac {1}{\sqrt {1^{2}+1^{2}}}=\dfrac {1}{\sqrt {2}}=\dfrac {\sqrt {2}}{2}$
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