Answer
$-18^{\circ}30'54''$
Work Step by Step
$-18.515^{\circ}=-(18^{\circ}+0.515^{\circ})$
$=-(18^{\circ}+0.515(60'))$
$=-(18^{\circ}+30.9')$
$=-(18^{\circ}+30'+0.9(60''))$
$=-(18^{\circ}+30'+54'')$
$=-18^{\circ}30'54''$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 5 - Trigonometric Functions - 5.1 Angles - 5.1 Exercises - Page 504: 69
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