Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - 5.1 Angles - 5.1 Exercises - Page 504: 46

Answer

$72^\circ 47'$

Work Step by Step

In this kind of subtraction, we subtract the degrees from the degrees and the minutes from the minutes: $90^\circ$ can be rewritten as: $89^\circ 60'$ $89^\circ 60'-17^\circ 13'=(89-17)^\circ+(60-13)'=72^\circ 47'$
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