Answer
$(6x-4)^\circ=80^\circ$
$(8x-12)^\circ=100^\circ$
Work Step by Step
If two angles are supplementary, the sum of the two angles is a straight angle ($180^\circ$):
$(6x-4)^\circ+(8x-12)^\circ=(14x-16)^\circ=180^\circ$
$14x-16=180$
$14x=180+16=196$
$x=14$
$(6x-4)^\circ=80^\circ$
$(8x-12)^\circ=100^\circ$
