Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - Summary Exercises on Inverse, Exponential, and Logarithmic Functions - Exercises - Page 449: 40

Answer

$2$

Work Step by Step

Since $\frac{1}{16}=\frac{1}{2^4}=(\frac{1}{2})^4$, we have $log_{1/2}(\frac{1}{16})=log_{1/2}(\frac{1}{2})^4=4$, thus $x=\sqrt 4=2$
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