Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - Summary Exercises on Inverse, Exponential, and Logarithmic Functions - Exercises - Page 449: 38

Answer

$-2$

Work Step by Step

Since $\frac{25}{16}=(\frac{5}{4})^2=(\frac{4}{5})^{-2}$, we have $x=log_{4/5}(\frac{25}{16})=log_{4/5}(\frac{4}{5})^{-2}=-2$
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