Answer
$-0.1303$
Work Step by Step
$log_{10}(\frac{20}{27})=log_{10}(\frac{2\cdot 10}{3^3})\\ =log_{10}2+log_{10}(10)-3log_{10}3\\ \approx0.3010+1-3(0.4771)\\ =-0.1303$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.3 Logarithmic Functions - 4.3 Exercises - Page 447: 98
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