Answer
$1.0791$
Work Step by Step
$log_{10}(12)=log_{10}(2^2\cdot 3)=2log_{10}2+log_{10}3\approx2(0.3010)+0.4771=1.0791$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.3 Logarithmic Functions - 4.3 Exercises - Page 447: 94
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