Answer
$\log _{a}\dfrac {xy}{m}$
Work Step by Step
$\log _{a}x+\log _{a}y=\log _{a}xy;\log _{a}x-\log _{a}y=\log _{a}\dfrac {x}{y}\Rightarrow $
$\log _{a}x+\log _{a}y-\log _{a}m=\log _{a}\dfrac {xy}{m}$
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