Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.3 Logarithmic Functions - 4.3 Exercises - Page 446: 77

Answer

$\dfrac {1}{2}\log _{2}5+\dfrac {3}{2}\log _{2}r-\dfrac {5}{2}\log _{2}z$

Work Step by Step

$\log _{2}\sqrt {\dfrac {5r^{3}}{z^{5}}}=\log _{2}5^{1/2}\times r^{3/2}\times z^{-5/2}=\dfrac {1}{2}\log _{2}5+\dfrac {3}{2}\log _{2}r-\dfrac {5}{2}\log _{2}z$
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