Answer
$1+\dfrac {1}{2}\log _{2}3-\log _{2}5$
Work Step by Step
$$\log _{2}\dfrac {2\sqrt {3}}{5}=\log _{2}2^{1}\times 3^{\dfrac {1}{2}}\times 5^{-1}=\log _{2}2+\log _{2}3^{1/2}-\log _{2}5=1+\dfrac {1}{2}\log _{2}3-\log _{2}5$$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.3 Logarithmic Functions - 4.3 Exercises - Page 446: 74
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
