Answer
$2\log _{3}2+\log _{3}p-\log _{3}q$
Work Step by Step
$\log _{3}\dfrac {4p}{q}=\log _{34}p-\log _{3}q=\log _{3}4+\log _{3}p-\log _{3}q=\log _{3}2^{2}+\log _{3}p-\log _{3}q=2\log _{3}2+\log _{3}p-\log _{3}q$
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