Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.3 Logarithmic Functions - 4.3 Exercises - Page 444: 6

Answer

$\frac{1}{6}$

Work Step by Step

Rewrite the equation as $36^x=\sqrt[3] 6$ or $6^{2x}=6^{1/3}$, thus $2x=\frac{1}{3}$ and $x=\frac{1}{6}$
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