Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.2 Exponential Functions - 4.2 Exercises - Page 433: 103

Answer

$2.5\%$

Work Step by Step

Given $P=1200, A=1500, n=4, t=9\ yr$, we have: $A=P(1+\frac{r}{n})^{nt}\longrightarrow 1500=1200(1+\frac{r}{4})^{4(9)} \longrightarrow r\approx 0.025 $ or $2.5\%$
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