Answer
$2.5\%$
Work Step by Step
Given $P=1200, A=1500, n=4, t=9\ yr$, we have:
$A=P(1+\frac{r}{n})^{nt}\longrightarrow 1500=1200(1+\frac{r}{4})^{4(9)} \longrightarrow r\approx 0.025 $ or $2.5\%$
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