Answer
$2.4\%$
Work Step by Step
Given $P=65000, A=65783.91, n=12, t=0.5\ yr$, we have:
$A=P(1+\frac{r}{n})^{nt}\longrightarrow 65783.91=65000(1+\frac{r}{12})^{12(0.5)} \longrightarrow r\approx 0.024 $ or $2.4\%$
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