Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.2 Exponential Functions - 4.2 Exercises - Page 433: 102

Answer

$2.4\%$

Work Step by Step

Given $P=65000, A=65783.91, n=12, t=0.5\ yr$, we have: $A=P(1+\frac{r}{n})^{nt}\longrightarrow 65783.91=65000(1+\frac{r}{12})^{12(0.5)} \longrightarrow r\approx 0.024 $ or $2.4\%$
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